How do you find the integral of 0 to the infinity of $x^(8/3) dx$ ?

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Answer 1 · 2015-04-10T18:20:45

$int_0^oo x^(8/3) dx = lim_(brarroo) int_0^b x^(8/3) dx$

$=lim_(b rarr oo) 3/11 x^(11/3)]_0^b = lim_(brarroo)3/11 b^(11/3)=oo$

The integral diverges.

How do you find the integral of 0 to the infinity of x^(8/3) dxx^(8/3) dx?