Question #efcdc

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Answer 1 · 2016-11-27T18:02:06

The answer is $=tanx$

$cscx=1/sinx$

$cotx=cosx/sinx$

$secx=1/cosx$

$cos^2x+sin^2x=1$

$tanx=sinx/cosx$

$(cscx-cotx)(secx+1)=(1/sinx-cosx/sinx)(1/cosx+1)$

$=((1-cosx)/sinx)((1+cosx)/cosx)$

$=(1-cos^2x)/(sinxcosx)$

$=sin^2x/(sinxcosx)$

$=sinx/cosx$

$=tanx$