Question #897a1

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Answer 1 · 2016-11-17T18:15:21

see below

$(1-cosx)/sinx + sinx/(1-cosx) = 2/sinx$

Left Side : $=(1-cosx)/sinx + sinx/(1-cosx)$

$=((1-cosx)(1-cos x) + sinx*sinx)/(sinx(1-cosx))$

$=(1-2cosx+cos^2x+sin^2x)/(sinx(1-cosx))$

$=(1-2cosx+1)/(sinx(1-cosx))$

$=(2-2cosx)/(sinx(1-cosx))$

$=(2(1-cosx))/(sinx(1-cosx))$

$=(2cancel((1-cosx)))/(sinxcancel((1-cosx)))$

$=2/sinx$

$:.=$ Right Side