How do you prove that $sinxtanx = secx- cosx$ ?

Question

1925 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-14T03:37:53

$sinx xx sinx/cosx = 1/cosx - cosx$

$sin^2x/cosx = 1/cosx - cos^2x/cosx$

$sin^2x/cosx = (1 - cos^2x)/cosx$

$sin^2x/cosx = sin^2x/cosx$

$LHS = RHS$

Identity proved!

Hopefully this helps!

How do you prove that sinxtanx = secx- cosxsinxtanx = secx- cosx?