Question #aadaa

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Answer 1 · 2016-11-08T17:45:35

see below

$(cscx+secx)/(sinx+cosx)=cscx/cosx$

Left Side: $=(cscx+secx)/(sinx+cosx)$

$=(1/sinx+1/cosx)/(sinx+cosx)$

$=((cosx+sinx)/(sinxcosx))/(sinx+cosx)$

$=cancel (cosx+sinx)/(sinxcosx) * 1/cancel(sinx+cosx)$

$=1/(sinxcosx)$

$=1/sinx*1/cosx$

$=cscx*1/cosx$

$=cscx/cosx$

$:. =$ Right Side