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Question #23e00

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Nov 3, 2016

$L H S = {sin}^{2} x (1 + {cot}^{2} x) - 1$ $LHS=sin^2x(1+cot^2x)-1$

$= {sin}^{2} x \times {csc}^{2} x - 1$ $=sin^2x xxcsc^2x-1$

$= 1 - 1 = 0 = R H S$ $=1-1=0=RHS$

Proved

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