Question #fa8db

Question

827 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-21T10:08:51

See Below

#sin (3x)=3sin x-4sin^3 x#

Use the formulas
#sin (A+B) = sin A cos B + cos A sin B#

#sin 2A = 2sin A cos A#

#cos 2A = 1- 2 sin ^ 2 A#

Left Side: #sin 3x=sin(2x+x)=sin2xcosx+cos2xsin x#

#=2sinx cosx cosx + (1-2sin^2 x)sin x#

#=2sinx cos^2 x+ sinx-2sin^3 x#

#=2sinx(1-sin^2 x) + sinx-2 sin^3 x#

#=2 sin x-2sin^3 x + sin x -2 sin^3 x#

#=3 sin x -4 sin^ 3 x#

#=# Right Side