Question #0733f

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Question #0733f

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Answer 1 · 2016-10-17T16:02:53

See proof below

Explanation:

Use the following ${cos}^{2} x + {sin}^{2} = 1$ $cos^2x+sin^2=1$
So $1 - {cos}^{2} x = {sin}^{2} x$ $1-cos^2x=sin^2x$
and $cot x = \frac{cos x}{sin x}$ $cotx=cosx/sinx$
So
$(1 - {cos}^{2} x) cot x = {sin}^{2} x \cdot \frac{cos x}{sin x} = sin x cos x$ $(1-cos^2x)cotx=sin^2x*cosx/sinx=sinxcosx$

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Question #0733f

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