Question #d8d7c

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Answer 1 · 2016-10-04T16:58:09

$(1+tanx+secx)(1+cotx-cscx)$

$=(1+sinx/cosx+1/cosx)(1+cosx/sinx-1/sinx)$

$=((cosx+sinx+1)/cosx)((sinx+cosx-1)/sinx)$

$=((cosx+sinx)^2-1)/(cosxsinx)$

$=(cos^2x+sin^2x+2sinxcosx-1)/(cosxsinx)$

$=(1+2sinxcosx-1)/(cosxsinx)$

$=(2sinxcosx)/(cosxsinx)$

$=2$