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Question #9a76f

1 Answer

Jul 9, 2016

$= 2$ $=2$

Explanation:

$\frac{{(1 - cos x)}^{2} + {sin}^{2} x}{1 - cos x}$ $((1-cosx)^2+sin^2x)/(1-cosx)$

$= \frac{1 - 2 cos x + {cos}^{2} x + {sin}^{2} x}{1 - cos x}$ $=(1-2cosx+cos^2x+sin^2x)/(1-cosx)$

$= \frac{1 - 2 cos x + 1}{1 - cos x}$ $=(1-2cosx+1)/(1-cosx)$

$= \frac{2 (1 - cos x)}{1 - cos x}$ $=(2(1-cosx))/(1-cosx)$

$= 2$ $=2$

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