A #0.240mol# quantity of dinitrogen gave #7.8mol# of ammonia. Does this make sense chemically?

Question

1467 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-15T04:09:02

#N_2(g) + 3H_2(g) rarr 2NH_3(g)#

You took #0.240*mol# dinitrogen and got #7.8*mol# of ammonia. Clearly, the problem as stated is incorrect.

The reaction quotient, #Q=([NH_3]^2)/([N_2][H_2]^3)#

Where the concentrations are not at equilibrium. You will have to rejig the figures.

A #0.240*mol# quantity of dinitrogen gave #7.8*mol# of ammonia. Does this make sense chemically?