A $0.240mol$ quantity of dinitrogen gave $7.8mol$ of ammonia. Does this make sense chemically?

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Answer 1 · 2016-06-15T04:09:02

$N_2(g) + 3H_2(g) rarr 2NH_3(g)$

You took $0.240*mol$ dinitrogen and got $7.8*mol$ of ammonia. Clearly, the problem as stated is incorrect.

The reaction quotient, $Q=([NH_3]^2)/([N_2][H_2]^3)$

Where the concentrations are not at equilibrium. You will have to rejig the figures.

A 0.240*mol0.240*mol quantity of dinitrogen gave 7.8*mol7.8*mol of ammonia. Does this make sense chemically?