Question #50e6d

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Answer 1 · 2016-05-04T18:41:07

see below

Left Side: $= sin x/(1-cosx) +(1-cosx)/sinx$

$=(sinx * sinx+(1-cosx)*(1-cos x))/(sinx(1-cosx))$

$=(sin^2 x + 1-2 cos x+cos^2x)/(sinx(1-cosx))$

$=(sin^2x+cos^2x+1-2cosx)/(sinx(1-cosx))$

$=(1+1-2cosx)/(sinx(1-cosx))$

$=(2-2cosx)/(sinx(1-cosx))$

$=(2(1-cosx))/(sinx(1-cosx))$

$=2 1/sinx$

$=2csc x$

$=$ Right Side