Find the value of (secx-1)(secx+1) and 1-sin^2theta/tan^2theta?

1 Answer
Jul 4, 2016

(secx-1)(secx+1)=tan^2x and 1-sin^2theta/tan^2theta=sin^2theta

Explanation:

(secx-1)(secx+1)=sec^2x-1=1+tan^2x-1=tan^2x

1-sin^2theta/tan^2theta=1-sin^2theta/(sin^2theta/cos^2theta)

= 1-sin^2thetaxxcos^2theta/sin^2theta

= 1-cos^2theta

= sin^2theta