Question #96bac
1 Answer
The equilibrium constant for this reaction is
I'll assume that the initial number of moles of
So, you know that you're dealing with an equilibrium between
If you start with only reactants in the flask, the fact that you have more product at equilibrium than you had reactants inititially tells you that
The initial concentrations of the reactants are
To determine the actual value of the equilibrium constant, use the ICE chart method (more here: https://en.wikipedia.org/wiki/RICE_chart).
.......
I......0.5.......0.5..............0
C...(-x).........(-x)............
E..0.5-x......0.5-x..........0.840
Since
This means that the equilibrium concentrations of the reactants will be
The value of
Since you've been a little inconsistent with the number of sig figs given, I'll round the answer to three sig figs (although that 1L volume would call for rounding to one sig fig)