Powers of the Binomial

Key Questions

  • Answer:

    The power of a binomial is the value of n in the binomial expression (a+x)^n.

    Explanation:

    For any value of n, the n^"th" power of a binomial is given by:

    (x+y)^n=x^n +nx^(n-1)y +(n(n-1))/2x^(n-2)y^2 + … + y^n

    The general formula for the expansion is:

    (x+y)^n = sum_(k=0)^n (n!)/((n-k)!k!)x^(n-k)y^k

    The coefficients for varying x and y can be arranged to form Pascal's triangle.

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    The n^"th" row in the triangle gives the coefficients of the terms in the (n-1)^"th" power of the polynomial.

  • Answer:

    (a+b)^3 = a^3+3a^2b+3ab^2+b^3

    Explanation:

    The coefficients 1, 3, 3, 1 can be found as a row of Pascal's triangle:

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    For other powers of a binomial use a different row of Pascal's triangle.

    For example:

    (a+b)^5 = a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5

    How about (2x-5)^3 or similar?

    Let a=2x and b=-5 to find:

    (2x-5)^3

    = (a+b)^3 = a^3+3a^2b+3ab^2+b^3

    =(2x)^3+3(2x)^2(-5)+3(2x)(-5)^2+(-5)^3

    =8x^3-60x^2+150x-125

  • Answer:

    I am not sure about what you need, but have a look:

    Explanation:

    If you have a binomial such as (a+b) and you square it you get:
    (a+b)^2
    but this is the same as:
    (a+b)(a+b)

    exactly as 4^2=4xx4.

    The result of (a+b)(a+b) is interesting because you need to multiply each term of the first bracket by each term of the second and add the results!
    (a+b)(a+b)=a*a+a*b+b*a+b*b=a^2+2ab+b^2

    Try by yourself with a difficult one: (a-b)^2 remembering to consider the signs of each term!

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