Infinite Sequences

Key Questions

  • It depends on the type of sequence.

    If the sequence is an arithmetic progression with first term a_1, then the terms will be of the form:

    a_n = a_1 + (n-1)b
    for some constant b.

    If the sequence is a geometric progression with first term a_1, then the terms will be of the form:

    a_n = a_1 * r^(n-1)
    for some constant r.

    There are also sequences where the next number is defined iteratively in terms of the previous 2 or more terms. An example of this would be the Fibonacci sequence:

    0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,...

    Each term is the sum of the two previous terms.

    The ratio of successive pairs of terms tends towards the golden ratio phi = 1/2 + sqrt(5)/2 ~= 1.618034

    The terms of the Fibonacci sequence are expressible by the formula:

    F_n = (phi^n-(-phi)^-n)/sqrt(5) (starting with F_0 = 0, F_1 = 1)

    In general an infinite sequence is any mapping from NN -> S for any set S. It can be defined in any way you like.

    Finite sequences are the same, except that they are mappings from a finite subset of NN consisting of those numbers less than some fixed limit, e.g. {n in NN: n <= 10}

  • A sequence is an infinite set of points which are ordered and a mapping can be associated with with that set and the set of natural numbers.

    The general notion of a sequence is that it is an infinite set with every element associated with a natural number even though all infinite sets may not be sequences.

    A sequence may be represented by, {x_n} where x_n is the nth element related to the a corresponding natural number.

    Thus if x_n = 1/n^2, the sequence may be given as,

    {1,1/4,1/9,1/16,....}

    For x_n = n^3 we shall have,

    {1, 8, 27, 64,....}

    Now for x_n = n we can have,

    {1,2,3,.....}

    This is indeed the set of naturals.

    However, there can be other ordered arrays of numbers which are sometimes referred at as sequences. They don't fit right with the definition I gave.

    Let's for example take a Fibonacci sequence.

    1,1,2,3,5,8,13,....

    This sequence is made by adding the previous two numbers on the list to form the next one and so on.

    There can be arithmetic sequences, like

    2,8,14,20,.... which has first term 2 and common difference 6.

    I like to call them progressions and reserve the word sequence for the definition I proposed in the first 2 paragraphs.

  • Answer:

    It depends.

    Explanation:

    There are many types of sequences. Some of the interesting ones can be found at the online encyclopedia of integer sequences at https://oeis.org/

    Let's look at some simple types:

    Arithmetic Sequences

    a_n = a_0 + dn

    e.g. 2, 4, 6, 8,...

    There is a common difference between each pair of terms.

    If you find a common difference between each pair of terms, then you can determine a_0 and d, then use the general formula for arithmetic sequences.

    Geometric Sequences

    a_n = a_0 * r^n

    e.g. 2, 4, 8, 16,...

    There is a common ratio between each pair of terms.

    If you find a common ratio between pairs of terms, then you have a geometric sequence and you should be able to determine a_0 and r so that you can use the general formula for terms of a geometric sequence.

    Iterative Sequences

    After the initial term or two, the following terms are defined in terms of the preceding ones.

    e.g. Fibonacci

    a_0 = 0
    a_1 = 1
    a_(n+2) = a_n + a_(n+1)

    For this sequence we find: a_n = (phi^n - (-phi)^(-n))/sqrt(5) where phi = (1+sqrt(5))/2

    There are many ways to make these iterative rules, so there is no universal method to provide an expression for a_n

    Polynomial Sequences

    If the terms of a sequence are given by a polynomial, then given the first few terms of the sequence you can find the polynomial.

    e.g.

    color(red)(1), 2, 4, 7, 11,...

    Form the sequence of differences of these values:

    color(red)(1), 2, 3, 4,...

    Form the sequence of differences of these values:

    color(red)(1), 1, 1,...

    Once you reach a constant sequence like this, pick out the initial terms from each sequence. In this case 1, 1 and 1.

    These form the coefficients of a polynomial expression:

    a_n = color(red)(1)/(0!) + (color(red)(1)*n)/(1!) + (color(red)(1)*n(n-1))/(2!)

    =n^2/2+n/2+1

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