How do you find the first five terms given #a_1=4# and #a_(n+1)=3a_n-6#? Precalculus Sequences Infinite Sequences 1 Answer sjc Sep 16, 2017 #{4,6,12,30,84}# Explanation: #a_(n+1)=3a_n-6# #a_1=4# #a_2=3a_1-6=3xx4-6=12-6=6# #a_3=3a_2-6=3xx6-6=18-6=12# #a_4=3a_3-6=3xx12-6=36-6=30# #a_5=3xxa_4-6=3xx30-6=90-6=84# Answer link Related questions What is a sequence? How does the Fibonacci sequence relate to Pascal's triangle? What is the Fibonacci sequence? How do I find the #n#th term of the Fibonacci sequence? How do you find the general term for a sequence? How do find the #n#th term in a sequence? What is the golden ratio? How does the golden ratio relate to the Fibonacci sequence? How do you determine if -10,20,-40,80 is an arithmetic or geometric sequence? How do you determine if 15,-5,-25,-45 is an arithmetic or geometric sequence? See all questions in Infinite Sequences Impact of this question 1364 views around the world You can reuse this answer Creative Commons License