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How do you write the first five terms of the sequence #a_n=(-1)^n(n/(n+1))#?

1 Answer

Jan 8, 2018

#-1,2, 2/3, -3/4, 4/5, - 5/6#

Explanation:

Given: #a_n = (-1)^n(n/(n+1))#

Let #n = 1: (-1)^1(1/(1+1)) = -1/2#

Let #n = 2: (-1)^2(2/(2+1)) = 2/3#

Let #n = 3: (-1)^3(3/(3+1)) = -3/4#

Let #n = 4: (-1)^4(4/(4+1)) = 4/5#

Let #n = 5: (-1)^5(5/(5+1)) = -5/6#

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