How do you graph $y=5-tan2(x-pi)$ ?

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Answer 1 · 2018-08-14T13:44:29

See explanation and graph.

$y = 5 - tan ( 2 ( x - pi ) = 5 + tan ( 2pi - 2x ) = 5 - tan 2x$ ,

$2x ne$ ( asymptotic zero of cos 2x ) ( 2k + 1 ) pi/2#

$rArr x ne ( 2k + 1 ) pi/4, k = 0, +-1, +-2, +-3, ...$

The period = $pi$ /2.

Amplitude of $oo$ -arm wave is 1/2( period ) = $pi/4$

Vertical shift is 5 $rArr$ axis is y = 5.

See graph, depicting all these aspects.
graph{(y-5+tan (2x))(y-5)(x-pi/4+0.01+0.005y)(x+pi/4--0.05+.005y)=0[-6 6 0 10]}

How do you graph y=5-tan2(x-pi) y=5-tan2(x-pi)?