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What is the antiderivative of #x/(x+1)#?

1 Answer

Jun 5, 2018

#x-ln(1+x)+C#

Explanation:

#int x/(1+x)dx#

#=int(x+1-1)/(1+x)dx#

#=int(x+1)/(x+1)-1/(x+1)dx#

#int1-1/(1+x)dx=x-ln(1+x)+C#

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