How do you write an equation of a circle with center at (-3,-10), d=24?

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Answer 1 · 2018-06-02T21:03:55

#(x-a)^2+(y-b)^2=r^2#

Where #(a,b)# are the coordinates of the center.

d=2r

24= 2r

#24/2=r#

r=12

Substituting values,

#(x+3)^2+(y+10)^2=144#

#x^2+6x+9+y^2+20y+100=144#

#x^2+y^2+6x+20y+100+9-144=0#

#x^2+y^2+6x+20y-35=0#