How do you solve the equation $- 2 x^{2} + 10 x + 22 = 4$ $-2x^2+10x+22=4$ by completing the square?

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Answer 1 · 2018-03-19T13:52:33

${(x - 2.5)}^{2} - 15.25 = 0$ $(x-2.5)^2-15.25=0$

$- 2 x^{2} + 10 x + 22 = 4$ $-2x^2+10x+22=4$

$- 2 x^{2} + 10 x + 18 = 0$ $-2x^2+10x+18=0$

$x^{2} - 5 x - 9 = 0$ $x^2-5x-9=0$

${(x - 2.5)}^{2} - {2.5}^{2} - 9 = 0$ $(x-2.5)^2-2.5^2-9=0$

${(x - 2.5)}^{2} - 6.25 - 9 = 0$ $(x-2.5)^2-6.25-9=0$

${(x - 2.5)}^{2} - 15.25 = 0$ $(x-2.5)^2-15.25=0$

How do you solve the equation -2x^2+10x+22=4−2x2+10x+22=4-2x^2+10x+22=4 by completing the square?