How do you graph #y=sin2x+1#?

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Answer 1 · 2018-03-11T05:21:36

graph{sin(2x)+1 [-10, 10, -5, 5]}

The amplitude of #y=sin(2x)+1# is 1 because there is no other co-efficient present in front of the function.

We know that the original graph is #y=sin(x)#

graph{ y= sin(x) [-10, 10, -5, 5]}

We are dilating the graph by a factor of #1/2# from the y axis
Therefore every x value is halved and the graph is

graph{sin(2x) [-10, 10, -5, 5]}

There is a translation of 1 unit to the positive direction of the y -axis, therefore we shift the entire graph up 1 unit.

graph{sin(2x)+1 [-10, 10, -5, 5]}

And there you have it, the graph of #y=sin(2x)+1#