How to integrate this? $intcolor(white).(3x^2-x+1)/(x^3-x^2)$

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Answer 1 · 2018-03-11T02:48:02

$3lnabs(x-1)+1/x+C$

$int(3x^2-x+1)/(x^3-x^2)dx=int(3x^2)/(x^2(x-1))dx -int(x-1)/(x^2(x-1))dx=int(3)/((x-1))dx-int1/x^2dx=3lnabs(x-1)+1/x+C$

How to integrate this? intcolor(white).(3x^2-x+1)/(x^3-x^2)intcolor(white).(3x^2-x+1)/(x^3-x^2)