Question #297e2

Question

↳Redirected from "What is the chemical formula of a diamond?"

2491 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-02T08:19:23

Both sides equals #sin^2t-cos^2t#

#(tan^2t-1)/sec^2t=(sin^2t/cos^2t-1)/(1/cos^2t)=sin^2t-cos^2t#

#(tant-cott)/(tant+cott)=(sint/cost-cost/sint)/(sint/cost+cost/sint)=((sin^2-cos^2t)/(sintcost))/((sin^2+cos^2t)/(sintcost))=sin^2t-cos^2t#

Answer 2 · 2016-11-06T01:22:39

#LHS=(tan^2T-1)/sec^2T#

#=(tan^2T-1)/(1+tan^2T)#

[Dividing numerator and denominator by #tanT# ]

#=(tan^2T/tanT-1/tanT)/(1/tanT+tan^2T/tanT)#

#=(tanT-cotT)/(cotT+tanT)=RHS#

Proved