How do you convert the Cartesian coordinates (-2,2) to polar coordinates?

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Answer 1 · 2015-10-19T01:24:59

#P=2.828/_135^(o)#

It is in the second quadrant so, the angle #90^(o) < phi < 180^(o)#

The module is:

#m^2=2^2+2^2#

#m^2=4+4#

#m=sqrt(8)=2.828#

The angle is:

#phi=tan^-1(-2/2)+180#

#phi=135^(o)#

#P=2.828/_135^(o)#