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How do you find the antiderivative of #4/x^2#?

1 Answer

Apr 14, 2015

#=-4/(x)+C#

Solution

#int4/(x^2)dx#

#=int4x^-2dx#

#=4intx^-2dx#

#=4.(x^(-2+1))/(-2+1)+C#

#=4.(x^-1)/(-1)+C#

#=-4/(x^1)+C#

#=-4/(x)+C#

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