What are five basic properties of definite integrals?

Question

6716 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-10-03T21:29:47

Is this what you have in mind?

$\int_{a}^{a} f (x) d x = 0$ $int_a^a f(x) dx=0$
$\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x$ $int_a^b f(x) dx=-int_b^a f(x) dx$
$\int_{a}^{b} [f (x) + g (x)] d x = \int_{a}^{b} f (x) d x + \int_{a}^{b} g (x) d x$ $int_a^b [f(x)+g(x)]dx=int_a^b f(x) dx+int_a^b g(x) dx$
$\int_{a}^{b} k f (x) d x = k \int_{a}^{b} f (x) d x$ $int_a^b k f(x)dx=k int_a^b f(x) dx$
$\int_{a}^{b} f (x) d x = \int_{a}^{c} f (x) d x + \int_{c}^{b} f (x) d x$ $int_a^b f(x) dx=int_a^c f(x) dx + int_c^b f(x) dx$

I hope that this was helpful.