What is the vertex form of #y= x^2+9x-22 #?

1 Answer
Alan P.
Dec 24, 2015

#y=(x-(-9/2))^2+(-169/4)#

Explanation:

General vertex form:
#color(white)("XXX")y=(x-a)^2+b# with vertex at #(a,b)#

#rarrcolor(white)("XXX")y=x^2+9x-22#

#rarrcolor(white)("XXX")y=x^2+9xcolor(red)(+(9/2)^2)-22color(red)(-(9/2)^2)#

#rarrcolor(white)("XXX")y=(x+9/2)^2-22-81/4#

#rarrcolor(white)("XXX")y=(x-(-9/2))^2+(-169/4)#

which is the vertex form with vertex at #(-9/2,-169/4)#

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