What is the vertex form of $y=x^2-6x+6$ ?

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Answer 1 · 2015-03-12T22:48:24

The vertex form of an equation is in the form:
$y = (x + a)^2 + b$

$(x-a)^2$ when expanded is $x^2 -2ax +a^2$

for the given equation, it follows that
$2ax = -6x$
$rarr a=-3$

$(x-3)^2 = x^2 - 6x +9$

comparing this to the given equation, we see that
$b = -3$

So the vertex form of the given equation is
$y = (x-3)^2 - 3$

What is the vertex form of y=x^2-6x+6y=x^2-6x+6?