What is the vertex form of #y=x^2-4x-3#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Alan P. Dec 24, 2015 #y=(x-2)^2+(-7)# with vertex at #(2,-7)# Explanation: General vertex form: #color(white)("XXX")y=(x-a)^2+b# with vertex at #(a,b)# Given: #color(white)("XXX")y=x^2-4x-3# Complete the square: #color(white)("XXX")y=x^2-4xcolor(green)(+4)-3color(green)(-4)# #color(white)("XXX")y=(x-2)^2-7# #color(white)("XXX")y=(x-2)^2+(-7)# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4838 views around the world You can reuse this answer Creative Commons License