What is the vertex form of #2y=(3x -3)(x - 5) #?

1 Answer
Jan 27, 2016

#y=3/2(x-3)^2+(-6)# with vertex at #(3,-6)#

Explanation:

The vertex form of a parabola is
#color(white)("XXX") y= m(x-a)^2+b#
for a parabola with center at #(a,b)#

#2y=(3x-3)(x-5)#

#rarr 2y=3(x-1)(x-5)#

#rarr 2/3y =x^2-6x+5#

#rarr 2/3y=(x^2-6x+9) +5 (-9)#

#rarr 2/3 y = (x-3)^2-4#

#rarr y=3/2(x-3)^2 - 3/2xx4#

#rarr y = 3/2(x-3)^2 + (-6)#

graph{((3x-3)(x-5))/2 [-1.27, 9.823, -7.815, -2.266]}