What is the value of (n!) by formula?

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Answer 1 · 2016-04-28T13:07:38

Please see below.

$n$ factorial is given by

$n! =nxx(n-1)xx(n-2)xx........xx3xx2xx1$

it can also be written as

$n! = nxx(n-1)!$

$1! =1$

$2! =2xx1=2$

$3! = 3xx2xx1=6$

$4! = 4xx3xx2xx1=24$

$5! =5xx4xx3xx2xx1=120$

$6! =6xx5xx4xx3xx2xx1=720$ and so on.