How do you write 2 7/8 as improper fraction?

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How do you write 2 7/8 as improper fraction?

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Answer 1 · 2018-05-22T16:40:56

$2 \frac{7}{8} = 2 + \frac{7}{8} = (\frac{8}{8} \times 2) + \frac{7}{8} = \frac{16}{8} + \frac{7}{8} = \frac{16 + 7}{8} = \frac{23}{8}$ $2 7/8 = 2 + 7/8 = (8/8 xx 2) + 7/8 = 16/8 + 7/8 = (16 + 7)/8 = 23/8$

Answer 2 · 2018-05-22T16:41:29

$\frac{23}{8}$ $23/8$

Explanation:

$2$ $2$ $\frac{7}{8}$ $7/8$

Do

$2 \times 8 = 16$ $2 xx8=16$

$16 + 7 = 23$ $16+7=23$

So

$2 \frac{7}{8} = \frac{23}{8}$ $2 7/8 = 23/8$

Answer 3 · 2018-05-22T16:42:13

$\Rightarrow \frac{23}{8}$ $=>23/8$

Explanation:

Think of the first number as a count of how many $1$ $1$ s you have. You can express $1$ $1$ as a fraction where the numerator and denominator are equal. In this case, it would useful to use $1 = \frac{8}{8}$ $1=8/8$ . An improper fraction is simply a sum of both terms present in the mixed number.

So our improper fraction would be:

$2 + \frac{7}{8}$ $2 + 7/8$

$= 2 \cdot \frac{8}{8} + \frac{7}{8}$ $=2*8/8 + 7/8$

$= \frac{16}{8} + \frac{7}{8}$ $=16/8 + 7/8$

We have a common denominator, we can combine the fractions:

$= \frac{16 + 7}{8}$ $=(16+7)/8$

$= \frac{23}{8}$ $=23/8$

This cannot be reduced further.

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How do you write 2 7/8 as improper fraction?

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