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What is the the vertex of #y=(x -5)^2 + 12x -36#?

1 Answer

Apr 6, 2016

vertex: #(x,y)= (-1,-12)#

Explanation:

Given
#color(white)("XXX")y=(x-5)^2+12x-36#

Convert into the general vertex form: #y=(x-a)^2+b# with vertex at #(a,b)#

#color(white)("XXX")y=(x^2-10x+25)+12x-36#

#color(white)("XXX")y=x^2+2x+1 -12#

#color(white)("XXX")y=(x+1)^2-12#

Graph of #y=(x-5)^2+12x-36#
graph{(x-5)^2+12x-36 [-6.696, 3.17, -12.26, -7.33]}

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