# How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=0?

May 29, 2018

$x = - 2$

#### Explanation:

Your quadratic equations is in standard form $a {x}^{2} + b x + c$ so the x-coordinate of the vertex (also called the axis of symmetry) is found with the formula:

$a o s = \frac{- b}{2 a}$

$4 {x}^{2} + 16 x + 12$

$a o s = \frac{- 16}{2 \cdot 4} = - 2$

graph{4x^2+16x+12 [-10, 10, -5, 5]}