What is the square root of x^12? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Alan P. Sep 11, 2015 #sqrt(x^12) = x^6# (or possibly #-x^6# if you want to include the non-principal square root) Explanation: In general #(b^a)^c = b^(ca)# So #(x^6)^2 = x^(2xx6) = x^12# or reversed #x^12 = (x^6)^2# Therefore #sqrt(x^12) = sqrt((x^6)^2) = x^6# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 20498 views around the world You can reuse this answer Creative Commons License