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What is the square root of x^12?

1 Answer

Sep 11, 2015

#sqrt(x^12) = x^6# (or possibly #-x^6# if you want to include the non-principal square root)

Explanation:

In general #(b^a)^c = b^(ca)#

So #(x^6)^2 = x^(2xx6) = x^12#
or reversed
#x^12 = (x^6)^2#

Therefore
#sqrt(x^12) = sqrt((x^6)^2) = x^6#

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