How do you simplify $^{5} \sqrt{96}$ $""^5sqrt(96)$

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Answer 1 · 2014-10-25T16:22:16

$\sqrt[5]{96}$ $root 5 96$

$\Rightarrow \sqrt[5]{2^{5} \cdot 3}$ $=> root 5 (2^5*3)$

$\Rightarrow \sqrt[5]{2^{5}} \cdot \sqrt[5]{3}$ $=> root 5 (2^5) * root 5 3$

$\Rightarrow 2 \sqrt[5]{3}$ $=> 2root 5 3$

Answer 2 · 2014-10-25T16:25:57

Since $96 = 2^{5} \cdot 3$ $96=2^5cdot3$ ,

$\sqrt[5]{96} = \sqrt[5]{2^{5} \cdot 3}$ $root[5]{96}=root[5]{2^5cdot3}$

by distributing the 5th-root,

$= \sqrt[5]{2^{5}} \cdot \sqrt[5]{3}$ $=root[5]{2^5}cdot root[5]{3}$

by cancelling out the 5th-power and the 5th-root,

$= 2 \sqrt[5]{3}$ $=2 root[5]{3}$ .

I hope that this was helpful.

How do you simplify 5√96 ""^5sqrt(96)