What is the #sqrt(x^2 + 4x + 4)#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Konstantinos Michailidis · Alan P. Sep 16, 2015 It is #abs(x+2)# Explanation: #sqrt(x^2+4x+4)=sqrt((x+2)^2)=abs(x+2)#. #x^2+4x+4# can be simplified to #(x+2)^2# and when square rooted it would be #(x+2)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 2418 views around the world You can reuse this answer Creative Commons License