What is the slope of #r=tantheta^2-theta^2-theta# at #theta=(3pi)/8#? Calculus Polar Curves Determining the Slope and Tangent Lines for a Polar Curve 1 Answer Lucy Apr 14, 2018 #(dr)/(d theta) = 67.88# Explanation: #r=tantheta^2-theta^2-theta# #(dr)/(d theta) = 2theta(sectheta^2)^2-2theta-1# At #theta =(3pi)/8# #(dr)/(d theta ) = 2times(3pi)/8times(sec((3pi)/8)^2)^2-2times(3pi)/8-1# #(dr)/(d theta) = 67.88# Answer link Related questions How do you find the slope of the tangent line to a polar curve? How do you find the slope of a polar curve? How do you find the equation of the tangent line to the polar curve #r=3+8sin(theta)# at #theta=pi/6# ? How do you find the slope of the polar curve #r=3+8sin(theta)# at #theta=pi/6# ? How do you find the slope of the polar curve #r=cos(2theta)# at #theta=pi/2# ? How do you find the slope of the polar curve #r=1+sin(theta)# at #theta=pi/4# ? How do you find the slope of the polar curve #r=3sec(2theta)# at #theta=pi/6# ? How do you find the equation of the tangent lines to the polar curve #r=sin(2theta)# at #theta=2pi# ? How do you find the equation of the tangent lines to the polar curve #r=4cos(theta)# at #theta=0# ? What is the slope of #x-2y=2#? See all questions in Determining the Slope and Tangent Lines for a Polar Curve Impact of this question 1307 views around the world You can reuse this answer Creative Commons License