What is the slope of a line perpendicular to $2y=-6x-10$ ?

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Answer 1 · 2014-09-28T02:29:57

The slope of a perpendicular line is the negative reciprocal, $-1/m$ , where $m$ is the slope of the given line.

Let's begin by putting the current equation in standard form.

$2y=-6x-10$

$6x+2y=-10$

The slope of this line is $-(A/B)=-(6/2)=-(3)=-3$

The negative reciprocal is $-1/m=-(1/(-3))=1/3$

What is the slope of a line perpendicular to 2y=-6x-102y=-6x-10?