How do I find the x-intercept of an equation in the form $y = m x + b$ $y = mx + b$ ?

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Answer 1 · 2014-10-07T03:15:23

The coordinates of a line or point on the x-axis will always have a $y$ $y$ coordinate of $0$ $0$ .

The following are examples of coordinates that lie on the $x$ $x$ -axis.

$(- \frac{3 π}{2}, 0)$ $(-(3pi)/2,0)$
$(0, 0)$ $(0,0)$ the origin
$(- 2, 0)$ $(-2,0)$
$(3, 0)$ $(3,0)$
$(\frac{π}{2}, 0)$ $(pi/2,0)$

To find the $x$ $x$ -intercept you would substitute in the value of $0$ $0$ for $y$ $y$ variable and then solve for the $x$ $x$ variable.

Example:

$y = 2 x + 6$ $y=2x+6$

$0 = 2 x + 6$ $0=2x+6$

$- 6 = 2 x$ $-6=2x$

$- \frac{6}{2} = \frac{2 x}{2}$ $-6/2=(2x)/2$

$- 3 = x$ $-3=x$

$(- 3, 0) \to$ $(-3,0) ->$ The y-intercept

How do I find the x-intercept of an equation in the form y=mx+by = mx + b?