What is the period of $y = cot (x - (\frac{π}{6}))$ $y = cot (x-(pi/6))$ and how would I graph this?

Question

What is the period of $y = cot (x - (\frac{π}{6}))$ $y = cot (x-(pi/6))$ and how would I graph this?

1 Answer

Related questions

How do you find the asymptotes for the cotangent function?
How do you graph tangent and cotangent functions?
How do you Sketch the graph of $y = - 2 + cot (\frac{1}{3}) x$ $y=-2+cot(1/3)x$ over the interval $[0, 6 π]$ $[0, 6pi]$ ?
How do you graph $y = - 3 tan (x - (\frac{π}{4}))$ $y=-3tan(x-(pi/4))$ over the interval $[- π, 2 π]$ $[-pi, 2pi]$ ?
How do you sketch a graph of $h (x) = 5 + \frac{1}{2} sec 4 x$ $h(x)=5+frac{1}{2} \sec 4x$ over the interval $[0, 2 π]$ $[0,2pi]$ ?
What is the amplitude, period and frequency for the function $y = - 1 + \frac{1}{3} cot 2 x$ $y=-1+\frac{1}{3} \cot 2x$ ?
How do you graph $y = 3 sec (2 x)$ $y = 3 sec(2x)$ ?
How do you graph $y = tan (2 x + \frac{π}{4})$ $y=tan(2x+pi/4)$ ?
What is the domain of $y = tan (x) + 2$ $y = tan(x) + 2$ ?
How do you graph $csc (x - \frac{π}{2})$ $csc(x-pi/2)$ ?

Impact of this question

4240 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-25T04:09:23

The period is Pi
Given an arc AM = x on the trig unit circle, with point B at the top. From the extremity M rotates clockwise an arc MN = Pi/6. Next, prolong the radius ON until it meets the horizontal tangent axis BZ at point P. The measure of segment BP is the value of cot x.

Science

Math

Humanities

... and beyond

What is the period of $y = cot (x - (\frac{π}{6}))$ $y = cot (x-(pi/6))$ and how would I graph this?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the period of y=cot(x−(π6))y = cot (x-(pi/6)) and how would I graph this?

1 Answer

Related questions

Impact of this question

What is the period of $y = cot (x - (\frac{π}{6}))$ $y = cot (x-(pi/6))$ and how would I graph this?