What is the period and frequency for #sin(2pi t / 5)#?

1 Answer
Alan P.
Aug 23, 2015

period of #sin((2pi)/5t) = 5#

frequency of #sin((2pi)/5t) = 1/5#

Explanation:

#sin(theta)# has a period of #2pi# relative to #theta#

#rArr sin((2pi)/5t)# has a period of #2pi# relative to #(2pi)/5t#

#rArr Sin((2pi)/5t)# has a period of #(2pi)/((2pi)/5) = 5# relative to #t#

frequency is the reciprocal of period

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
13576 views around the world
You can reuse this answer
Creative Commons License