What is the period and frequency for #sin(2pi t / 5)#?

1 Answer
Aug 23, 2015

period of #sin((2pi)/5t) = 5#

frequency of #sin((2pi)/5t) = 1/5#

Explanation:

#sin(theta)# has a period of #2pi# relative to #theta#

#rArr sin((2pi)/5t)# has a period of #2pi# relative to #(2pi)/5t#

#rArr Sin((2pi)/5t)# has a period of #(2pi)/((2pi)/5) = 5# relative to #t#

frequency is the reciprocal of period