What is the molality of a solution of phosphoric acid, $H_{3} P O_{4}$ $H_3PO_4$ that contains 24.5 g of phosphoric acid (molar mass 98.0 g) in 100 g of $H_{2} O$ $H_2O$ ?

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What is the molality of a solution of phosphoric acid, $H_{3} P O_{4}$ $H_3PO_4$ that contains 24.5 g of phosphoric acid (molar mass 98.0 g) in 100 g of $H_{2} O$ $H_2O$ ?

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Answer 1 · 2016-07-06T00:50:24

The molality is 2.50 mol/kg.

Explanation:

The formula for molality $b$ $b$ is

$color(blue)(|bar(ul(color(white)(a/a) b = "moles of solute"/"kilograms of solvent"color(white)(a/a)|)))" "$

$"Moles of H"_3"PO"_4 = 24.5 color(red)(cancel(color(black)("g H"_3"PO"_4))) × ("1 mol H"_3"PO"_4)/(98.0 color(red)(cancel(color(black)("g H"_3"PO"_4)))) = "0.250 mol H"_3"PO"_4$

$"Mass of solvent" = "100 g" = "0.100 kg"$

∴ $b = "0.250 mol"/"0.100 kg" = "2.50 mol/kg"$

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What is the molality of a solution of phosphoric acid, $H_{3} P O_{4}$ $H_3PO_4$ that contains 24.5 g of phosphoric acid (molar mass 98.0 g) in 100 g of $H_{2} O$ $H_2O$ ?

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What is the molality of a solution of phosphoric acid, H_3PO_4H3PO4H_3PO_4 that contains 24.5 g of phosphoric acid (molar mass 98.0 g) in 100 g of H_2OH2OH_2O?

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What is the molality of a solution of phosphoric acid, $H_{3} P O_{4}$ $H_3PO_4$ that contains 24.5 g of phosphoric acid (molar mass 98.0 g) in 100 g of $H_{2} O$ $H_2O$ ?