What is the equation of the line with slope # m= -5 # that passes through # (-1,-3) #?

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Answer 1 · 2018-04-24T01:00:54

#y =-5x-8#

Since we are provided the slope and a point on the line we can use the equation for point slope form of the equation of a line.

#y-y_1 =m(x-x_1)#

Where #m=# slope and the point is #(x_1,y_1)#

For this situation #m=-5# and a point of #(-1,-3)#

#m=-5#
#x_1=-1#
#y_1=-3#

#y-y_1 =m(x-x_1)#

Plug in the values
#y-(-3) =-5(x-(-1))#

Simplify the signs
#y+3 =-5(x+1)#

Use distributive property to eliminate the parenthesis
#y+3 =-5x-5#

Use the additive inverse to isolate the #y# value
#y cancel(+3) cancel(-3) =-5x-5-3#

Simplify the common terms
#y =-5x-8#