What is the equation of the line with slope # m= -3/5 # that passes through # (-2,-3) #?

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Answer 1 · 2016-01-12T16:36:24

If the slope of the line and any one point on the line are given then we find the equation of the line as

#y-y_1=m(x-x_1)#

Where #m# is the slope and #(x_1,y_1)# are the coordinates of the point.

Here #m=-3/5# and #(x_1,y_1)=(-2,-3)#.

Therefore, the equation of line is
#y-(-3)=-3/5{x-(-2)}#

#implies y+3=-3/5(x+2)#

#implies -5y-15=3x+6#

#implies 3x+5y+21=0#