What is the equation of the line with slope # m= 11/3 # that passes through # (-17/15,-15/24) #?

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Answer 1 · 2016-01-08T06:34:40

3960x-1080y+3813=0#

If #A(x_1,y_1)# is a point on the line and #m# is the slope of the line then the equation of line is given by
#y-y_1=m(x-x_1)#

Here #m=11/3# and #A=(-17/15,-15/24)#

The required line is
#implies y-(-15/24)=11/3(x-(-17/15))#

#implies y+15/24=11/3(x+17/15)#

#implies y+15/24=(11x)/3+(187)/45#

#implies 1080y+675=3960x+4488#
#implies 3960x-1080y+3813=0#