What is the equation of the line with slope # m= -1/25 # that passes through # (7/5, 1/10) #?

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Answer 1 · 2016-06-25T12:47:33

In point slope form:

#y - 1/10 = -1/25(x-7/5)#

In slope intercept form:

#y = -1/25x+39/250#

Given a slope #m# and a point #(x_1, y_1)# through which a line passes, its equation can be written in point slope form:

#y - y_1 = m(x-x_1)#

In our example, #m=-1/25# and #(x_1, y_1) = (7/5, 1/10)#, so we get the equation:

#y - 1/10 = -1/25(x-7/5)#

Expanding and rearranging, this can be expressed as:

#y = -1/25x+39/250#

which is in slope intercept form:

#y = mx+b#

with #m=-1/25# and #b=39/250#

graph{(y - 1/10 + 1/25(x-7/5))(x^2+(y-39/250)^2-0.0017)((x-7/5)^2+(y-1/10)^2-0.0017)=0 [-1.76, 3.24, -1.17, 1.33]}