What is the equation of the line perpendicular to $y = - \frac{3}{8} x$ $y=-3/8x$ that passes through $(- 8, 8)$ $(-8,8)$ ?

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Answer 1 · 2016-07-06T21:45:39

$y = \frac{8}{3} x + 29 \frac{1}{3}$ $y= 8/3x +29 1/3$

If lines are perpendicular, then the slope of one is the negative reciprocal of the other.

So, $\frac{1}{2}$ $1/2$ is perpendicular to $- 2$ $-2$

$- \frac{2}{3}$ $-2/3$ is perpendicular to $\frac{3}{2}$ $3/2$

$\frac{5}{4}$ $5/4$ is perpendicular to $- \frac{4}{5}$ $-4/5$

In this case, $- \frac{3}{8}$ $" "-3/8$ is perpendicular to $\frac{8}{3}$ $8/3$

We also have the point $(- 8, 8)$ $(-8,8)$

Use the formula $(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m(x-x_1)$

$y - 8 = \frac{8}{3} (x - (- 8))$ $y-8=8/3(x-(-8))$

$y = \frac{8}{3} x + \frac{64}{3} + 8$ $y = 8/3x +64/3 +8$

$y = \frac{8}{3} x + 29 \frac{1}{3}$ $y= 8/3x +29 1/3$

What is the equation of the line perpendicular to y=−38xy=-3/8x that passes through (−8,8) (-8,8) ?