What is the equation of the line perpendicular to $y=-3/8x$ that passes through $(-8,8)$ ?

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Answer 1 · 2016-07-06T21:45:39

$y= 8/3x +29 1/3$

If lines are perpendicular, then the slope of one is the negative reciprocal of the other.

So, $1/2$ is perpendicular to $-2$

$-2/3$ is perpendicular to $3/2$

$5/4$ is perpendicular to $-4/5$

In this case, $" "-3/8$ is perpendicular to $8/3$

We also have the point $(-8,8)$

Use the formula $(y-y_1)=m(x-x_1)$

$y-8=8/3(x-(-8))$

$y = 8/3x +64/3 +8$

$y= 8/3x +29 1/3$

What is the equation of the line perpendicular to y=-3/8x y=-3/8x that passes through (-8,8) (-8,8) ?